This is the Base.Varieties.FreeAlgebras module of the Agda Universal Algebra Library.
First we will define the relatively free algebra in a variety, which is the “freest” algebra among (universal for) those algebras that model all identities holding in the variety. Then we give a formal proof of Birkhoff’s theorem which says that a variety is an equational class. In other terms, a class 𝒦
of algebras is closed under the operators H
, S
, and P
if and only if 𝒦
is the class of algebras that satisfy some set of identities.
{-# OPTIONS --without-K --exact-split --safe #-} open import Level using ( Level ) open import Overture using ( 𝓞 ; 𝓥 ; Signature ) module Base.Varieties.FreeAlgebras {α : Level} {𝑆 : Signature 𝓞 𝓥} where -- Imports from Agda and the Agda Standard Library --------------------- open import Agda.Primitive using ( _⊔_ )renaming ( Set to Type ) open import Data.Product using ( _,_ ; Σ-syntax ; _×_ ) renaming ( proj₁ to fst ; proj₂ to snd ) open import Function using ( _∘_ ) open import Level using ( suc ) open import Relation.Binary using ( IsEquivalence ) renaming ( Rel to BinRel ) open import Relation.Unary using ( Pred ; _∈_ ; _⊆_ ; {_} ; _∪_ ) open import Axiom.Extensionality.Propositional using () renaming (Extensionality to funext) open import Relation.Binary.PropositionalEquality as ≡ using ( _≡_ ; module ≡-Reasoning ) -- Imports from the Agda Universal Algebra Library ------------------------------------------- open import Overture using ( ∣_∣ ; ∥_∥ ; _∙_ ; _⁻¹ ) open import Base.Functions using ( IsSurjective ) open import Base.Relations using ( kernel ; ⟪_⟫ ) open import Base.Equality using ( SwellDef ; swelldef ; is-set ; blk-uip ; hfunext ; DFunExt; pred-ext ) open import Base.Algebras {𝑆 = 𝑆} using ( Algebra ; Lift-Alg ; compatible; _̂_ ; ov ; ⨅ ; Con; mkcon ; IsCongruence ) open import Base.Homomorphisms {𝑆 = 𝑆} using ( hom ; epi ; epi→hom ; kercon ; ker-in-con ; πker ; ker[_⇒_]_↾_ ; ∘-hom ) using ( ⨅-hom-co ; HomFactor ; HomFactorEpi ; _≅_ ; ≅-refl ; ≅-sym ; Lift-≅ ) open import Base.Terms {𝑆 = 𝑆} using ( Term ; 𝑻 ; free-lift ; lift-hom ; free-unique ; _⟦_⟧ ) using ( lift-of-epi-is-epi ; comm-hom-term; free-lift-interp ) open import Base.Subalgebras {𝑆 = 𝑆} using ( _≤_ ; FirstHomCorollary|Set ) open import Base.Varieties.EquationalLogic {𝑆 = 𝑆} using ( _⊫_≈_; _⊧_≈_; Th; Mod ) open import Base.Varieties.Closure {𝑆 = 𝑆} using ( S ; P ; V ) open import Base.Varieties.Preservation {𝑆 = 𝑆} using ( module class-products-with-maps ; class-ids-⇒ ; class-ids ; SP⊆V') open Term ; open S ; open V 𝓕 𝓕⁺ : Level 𝓕 = ov α 𝓕⁺ = suc (ov α) -- (this will be the level of the free algebra)
Recall, we proved in the Base.Terms.Basic module that the term algebra 𝑻 X
is absolutely free in the class of all 𝑆
-structures.
In this section, we formalize, for a given class 𝒦
of 𝑆
-algebras, the (relatively) free algebra in S(P 𝒦)
over X
.
We use the next definition to take a free algebra for a class 𝒦
and produce the free algebra in 𝒦
.
Let Θ(𝒦, 𝑨) := {θ ∈ Con 𝑨 : 𝑨 / θ ∈ (S 𝒦)}
, and let ψ(𝒦, 𝑨) := ⋂ Θ(𝒦, 𝑨)
.
(Notice that Θ(𝒦, 𝑨)
may be empty, in which case ψ(𝒦, 𝑨) = 1
and then 𝑨 / ψ(𝒦, 𝑨)
is trivial.)
The free algebra is constructed by applying the definitions of θ
and ψ
to the special case in which 𝑨
is the algebra 𝑻 X
of 𝑆
-terms over X
.
Since 𝑻 X
is free for (and in) the class of all 𝑆
-algebras, it follows that 𝑻 X
is free for every class 𝒦
of 𝑆
-algebras. Of course, 𝑻 X
is not necessarily a member of 𝒦
, but if we form the quotient of 𝑻 X
modulo the congruence ψ(𝒦, 𝑻 X)
, which we denote by 𝔽[ X ] := (𝑻 X) / ψ(𝒦, 𝑻 X)
, then it’s not hard to see that 𝔽[ X ]
is a subdirect product of the algebras in {(𝑻 𝑋) / θ}
, where θ
ranges over Θ(𝒦, 𝑻 X)
, so 𝔽[ X ]
belongs to SP(𝒦)
, and must therefore satisfy all identities modeled by all members of 𝒦
. Indeed, for each pair p q : 𝑻 X
, if 𝒦 ⊧ p ≈ q
, then p
and q
belong to the same ψ(𝒦, 𝑻 X)
-class, so p
and q
are identified in the quotient 𝔽[ X ]
.
The 𝔽[ X ]
that we have just defined is called the free algebra over 𝒦
generated by X
and (because of what we just observed) we may say that 𝔽[ X ]
is free in SP(𝒦)
.
Remarks. Since X
is not a subset of 𝔽[ X ]
, technically it doesn’t make sense to say “X
generates 𝔽[ X ]
.” But as long as 𝒦
contains a nontrivial algebra, we will have ψ(𝒦, 𝑻 𝑋) ∩ X² ≠ ∅
, and we can identify X
with X / ψ(𝒦, 𝑻 X)
which is a subset of 𝔽[ X ]
.
Before we attempt to represent the free algebra in Agda we construct the congruence ψ(𝒦, 𝑻 𝑋)
described above.
First, we represent the congruence relation ψCon
, modulo which 𝑻 X
yields the relatively free algebra, 𝔽[ X ] := 𝑻 X ╱ ψCon
. We let ψ
be the collection of identities (p, q)
satisfied by all subalgebras of algebras in 𝒦
.
module _ {X : Type α}(𝒦 : Pred (Algebra α) 𝓕) where ψ : Pred (∣ 𝑻 X ∣ × ∣ 𝑻 X ∣) 𝓕 ψ (p , q) = ∀(𝑨 : Algebra α)(sA : 𝑨 ∈ S{α}{α} 𝒦)(h : X → ∣ 𝑨 ∣ ) → (free-lift 𝑨 h) p ≡ (free-lift 𝑨 h) q
We convert the predicate ψ
into a relation by currying.
ψRel : BinRel ∣ 𝑻 X ∣ 𝓕 ψRel p q = ψ (p , q)
To express ψRel
as a congruence of the term algebra 𝑻 X
, we must prove that
ψRel
is compatible with the operations of 𝑻 X
(which are jsut the terms themselves) andψRel
it is an equivalence relation.open ≡-Reasoning ψcompatible : swelldef 𝓥 α → compatible (𝑻 X) ψRel ψcompatible wd 𝑓 {p} {q} ψpq 𝑨 sA h = γ where φ : hom (𝑻 X) 𝑨 φ = lift-hom 𝑨 h γ : ∣ φ ∣ ((𝑓 ̂ 𝑻 X) p) ≡ ∣ φ ∣ ((𝑓 ̂ 𝑻 X) q) γ = ∣ φ ∣ ((𝑓 ̂ 𝑻 X) p) ≡⟨ ∥ φ ∥ 𝑓 p ⟩ (𝑓 ̂ 𝑨) (∣ φ ∣ ∘ p) ≡⟨ wd (𝑓 ̂ 𝑨)(∣ φ ∣ ∘ p)(∣ φ ∣ ∘ q)(λ x → ψpq x 𝑨 sA h) ⟩ (𝑓 ̂ 𝑨) (∣ φ ∣ ∘ q) ≡⟨ (∥ φ ∥ 𝑓 q)⁻¹ ⟩ ∣ φ ∣ ((𝑓 ̂ 𝑻 X) q) ∎ ψIsEquivalence : IsEquivalence ψRel ψIsEquivalence = record { refl = λ 𝑨 sA h → ≡.refl ; sym = λ x 𝑨 sA h → (x 𝑨 sA h)⁻¹ ; trans = λ pψq qψr 𝑨 sA h → (pψq 𝑨 sA h) ∙ (qψr 𝑨 sA h) }
We have collected all the pieces necessary to express the collection of identities satisfied by all subalgebras of algebras in the class as a congruence relation of the term algebra. We call this congruence ψCon
and define it using the Congruence constructor mkcon
.
ψCon : swelldef 𝓥 α → Con (𝑻 X) ψCon wd = ψRel , mkcon ψIsEquivalence (ψcompatible wd)
To complete the proof of the HSP theorem, it remains to show that Mod X (Th (V 𝒦))
is contained in V 𝒦
; that is, every algebra that models the equations in Th (V 𝒦)
belongs to V 𝒦
. This will prove that V 𝒦
is an equational class. (The converse, that every equational class is a variety was already proved; see the remarks at the end of this module.)
We accomplish this goal by constructing an algebra 𝔽
with the following properties:
𝔽 ∈ V 𝒦
and
Every 𝑨 ∈ Mod X (Th (V 𝒦))
is a homomorphic image of 𝔽
.
We denote by ℭ
the product of all subalgebras of algebras in 𝒦
, and by homℭ
the homomorphism from 𝑻 X
to ℭ
defined as follows: homℭ := ⨅-hom-co (𝑻 X) 𝔄 hom𝔄
. Here, ⨅-hom-co
(defined in the Base.Homomorphisms.Properties module) takes the term algebra 𝑻 X
, a family {𝔄 : I → Algebra α}
of 𝑆
-algebras, and a family hom𝔄 : ∀ i → hom (𝑻 X) (𝔄 i)
of homomorphisms and constructs the natural homomorphism homℭ
from 𝑻 X
to the product ℭ := ⨅ 𝔄
. The homomorphism homℭ : hom (𝑻 X) (⨅ ℭ)
is “natural” in the sense that the i
-th component of the image of t : Term X
under homℭ
is the image ∣ hom𝔄 i ∣ t
of t
under the i-th homomorphism hom𝔄 i
.
Now we come to a step in our approach to formalizing the HSP theorem that turned out to be more technically challenging than we anticipated. We must prove that the free algebra embeds in the product ℭ
of all subalgebras of algebras in the class 𝒦
. This is really the only stage in the proof of Birkhoff’s theorem that requires the truncation assumption that ℭ
be a set (that is, ℭ
has the [UIP][] property). We will also need to assume several local function extensionality postulates and, as a result, the next submodule will take as given the parameter fe : (∀ a b → funext a b)
. This allows us to postulate local function extensionality when and where we need it in the proof. For example, if we want to assume function extensionality at universe levels 𝓥
and α
, we simply apply fe
to those universes: fe 𝓥 α
. (Earlier versions of the library used just a single global function extensionality postulate at the start of most modules, but we have since decided to exchange that elegant but crude option for greater precision and transparency.)
module _ {fe : DFunExt}{wd : SwellDef}{X : Type α} {𝒦 : Pred (Algebra α) 𝓕} where open class-products-with-maps {X = X}{fe 𝓕 α}{fe 𝓕⁺ 𝓕⁺}{fe 𝓕 𝓕} 𝒦
We begin by constructing ℭ
, using the techniques described in the section on products of classes.
-- ℭ is the product of all subalgebras of algebras in 𝒦. ℭ : Algebra 𝓕 ℭ = ⨅ 𝔄'
Observe that the inhabitants of ℭ
are maps from ℑ
to {𝔄 i : i ∈ ℑ}
. A homomorphism from 𝑻 X
to ℭ
is obtained as follows.
homℭ : hom (𝑻 X) ℭ homℭ = ⨅-hom-co 𝔄' (fe 𝓕 α){𝓕}(𝑻 X) λ i → lift-hom (𝔄' i)(snd ∥ i ∥)
As mentioned, the initial version of the agda-algebras library used the free algebra 𝔉
developed above. However, our new, more direct proof uses the algebra 𝔽
, which we now define, along with the natural epimorphism epi𝔽 : epi (𝑻 X) 𝔽
from 𝑻 X
to 𝔽
.
We now define the algebra 𝔽
, which plays the role of the free algebra, along with the natural epimorphism epi𝔽 : epi (𝑻 X) 𝔽
from 𝑻 X
to 𝔽
.
𝔽 : Algebra 𝓕⁺ 𝔽 = ker[ 𝑻 X ⇒ ℭ ] homℭ ↾ (wd 𝓥 (ov α)) epi𝔽 : epi (𝑻 X) 𝔽 epi𝔽 = πker (wd 𝓥 (ov α)) {ℭ} homℭ hom𝔽 : hom (𝑻 X) 𝔽 hom𝔽 = epi→hom 𝔽 epi𝔽 hom𝔽-is-epic : IsSurjective ∣ hom𝔽 ∣ hom𝔽-is-epic = snd ∥ epi𝔽 ∥
We will need the following facts relating homℭ
, hom𝔽
, and ψ
.
ψlemma0 : ∀ p q → ∣ homℭ ∣ p ≡ ∣ homℭ ∣ q → (p , q) ∈ ψ 𝒦 ψlemma0 p q phomℭq 𝑨 sA h = ≡.cong-app phomℭq (𝑨 , sA , h) ψlemma0-ap : {𝑨 : Algebra α}{h : X → ∣ 𝑨 ∣} → 𝑨 ∈ S{α}{α} 𝒦 → kernel ∣ hom𝔽 ∣ ⊆ kernel (free-lift 𝑨 h) ψlemma0-ap {𝑨}{h} skA {p , q} x = γ where ν : ∣ homℭ ∣ p ≡ ∣ homℭ ∣ q ν = ker-in-con {α = (ov α)}{ov α}{𝑻 X}{wd 𝓥 (suc (ov α))}(kercon (wd 𝓥 (ov α)) {ℭ} homℭ) {p}{q} x γ : (free-lift 𝑨 h) p ≡ (free-lift 𝑨 h) q γ = ((ψlemma0 p q) ν) 𝑨 skA h
We now use ψlemma0-ap
to prove that every map h : X → ∣ 𝑨 ∣
, from X
to a subalgebra 𝑨 ∈ S 𝒦
of 𝒦
, lifts to a homomorphism from 𝔽
to 𝑨
.
𝔽-lift-hom : (𝑨 : Algebra α) → 𝑨 ∈ S{α}{α} 𝒦 → (X → ∣ 𝑨 ∣) → hom 𝔽 𝑨 𝔽-lift-hom 𝑨 skA h = fst(HomFactor (wd 𝓥 (suc (ov α))) 𝑨 (lift-hom 𝑨 h) hom𝔽 (ψlemma0-ap skA) hom𝔽-is-epic)
The goal of this subsection is to prove that 𝒦
models ψ 𝒦
. In other terms, for all pairs (p , q) ∈ Term X × Term X
of terms, if (p , q) ∈ ψ 𝒦
, then 𝒦 ⊫ p ≈ q
.
Next we define the lift of the natural embedding from X
into 𝔽
. We denote this homomorphism by 𝔑 : hom (𝑻 X) 𝔽
and define it as follows.
open IsCongruence X↪𝔽 : X → ∣ 𝔽 ∣ X↪𝔽 x = ⟪ ℊ x ⟫ -- (the implicit relation here is ⟨ kercon (fe 𝓥 𝓕) ℭ homℭ ⟩ ) 𝔑 : hom (𝑻 X) 𝔽 𝔑 = lift-hom 𝔽 X↪𝔽
It turns out that the homomorphism so defined is equivalent to hom𝔽
.
open ≡-Reasoning hom𝔽-is-lift-hom : ∀ p → ∣ 𝔑 ∣ p ≡ ∣ hom𝔽 ∣ p hom𝔽-is-lift-hom (ℊ x) = ≡.refl hom𝔽-is-lift-hom (node 𝑓 𝒕) = ∣ 𝔑 ∣ (node 𝑓 𝒕) ≡⟨ ∥ 𝔑 ∥ 𝑓 𝒕 ⟩ (𝑓 ̂ 𝔽)(λ i → ∣ 𝔑 ∣(𝒕 i)) ≡⟨ wd-proof ⟩ (𝑓 ̂ 𝔽)(λ i → ∣ hom𝔽 ∣ (𝒕 i)) ≡⟨ (∥ hom𝔽 ∥ 𝑓 𝒕)⁻¹ ⟩ ∣ hom𝔽 ∣ (node 𝑓 𝒕) ∎ where wd-proof = wd 𝓥 (suc (ov α)) (𝑓 ̂ 𝔽) (λ i → ∣ 𝔑 ∣(𝒕 i)) (λ i → ∣ hom𝔽 ∣ (𝒕 i)) (λ x → hom𝔽-is-lift-hom(𝒕 x))
We need a three more lemmas before we are ready to tackle our main goal.
ψlemma1 : kernel ∣ 𝔑 ∣ ⊆ ψ 𝒦 ψlemma1 {p , q} 𝔑pq 𝑨 sA h = γ where f : hom 𝔽 𝑨 f = 𝔽-lift-hom 𝑨 sA h h' φ : hom (𝑻 X) 𝑨 h' = ∘-hom (𝑻 X) 𝑨 𝔑 f φ = lift-hom 𝑨 h h≡φ : ∀ t → (∣ f ∣ ∘ ∣ 𝔑 ∣) t ≡ ∣ φ ∣ t h≡φ t = free-unique (wd 𝓥 α) 𝑨 h' φ (λ x → ≡.refl) t γ : ∣ φ ∣ p ≡ ∣ φ ∣ q γ = ∣ φ ∣ p ≡⟨ (h≡φ p)⁻¹ ⟩ ∣ f ∣ ( ∣ 𝔑 ∣ p ) ≡⟨ ≡.cong ∣ f ∣ 𝔑pq ⟩ ∣ f ∣ ( ∣ 𝔑 ∣ q ) ≡⟨ h≡φ q ⟩ ∣ φ ∣ q ∎ ψlemma2 : kernel ∣ hom𝔽 ∣ ⊆ ψ 𝒦 ψlemma2 {p , q} x = ψlemma1 {p , q} γ where γ : (free-lift 𝔽 X↪𝔽) p ≡ (free-lift 𝔽 X↪𝔽) q γ = (hom𝔽-is-lift-hom p) ∙ x ∙ (hom𝔽-is-lift-hom q)⁻¹ ψlemma3 : ∀ p q → (p , q) ∈ ψ{X = X} 𝒦 → 𝒦 ⊫ p ≈ q ψlemma3 p q pψq {𝑨} kA h = goal where goal : (𝑨 ⟦ p ⟧) h ≡ (𝑨 ⟦ q ⟧) h goal = (𝑨 ⟦ p ⟧) h ≡⟨ free-lift-interp (wd 𝓥 α) 𝑨 h p ⟩ (free-lift 𝑨 h) p ≡⟨ pψq 𝑨 (siso (sbase kA) (≅-sym Lift-≅)) h ⟩ (free-lift 𝑨 h) q ≡⟨ (free-lift-interp (wd 𝓥 α) 𝑨 h q)⁻¹ ⟩ (𝑨 ⟦ q ⟧) h ∎
With these results in hand, it is now trivial to prove the main theorem of this subsection.
class-models-kernel : ∀ p q → (p , q) ∈ kernel ∣ hom𝔽 ∣ → 𝒦 ⊫ p ≈ q class-models-kernel p q x = ψlemma3 p q (ψlemma2 x) 𝕍𝒦 : Pred (Algebra 𝓕⁺) (suc 𝓕⁺) 𝕍𝒦 = V{α = α}{β = 𝓕⁺} 𝒦 kernel-in-theory' : kernel ∣ hom𝔽 ∣ ⊆ Th (V 𝒦) kernel-in-theory' {p , q} pKq = (class-ids-⇒ fe wd p q (class-models-kernel p q pKq)) kernel-in-theory : kernel ∣ hom𝔽 ∣ ⊆ Th 𝕍𝒦 kernel-in-theory {p , q} pKq vkA x = class-ids fe wd p q (class-models-kernel p q pKq) vkA x _↠_ : Type α → Algebra 𝓕⁺ → Type 𝓕⁺ X ↠ 𝑨 = Σ[ h ∈ (X → ∣ 𝑨 ∣) ] IsSurjective h 𝔽-ModTh-epi : (𝑨 : Algebra 𝓕⁺) → (X ↠ 𝑨) → 𝑨 ∈ Mod (Th 𝕍𝒦) → epi 𝔽 𝑨 𝔽-ModTh-epi 𝑨 (η , ηE) AinMTV = goal where φ : hom (𝑻 X) 𝑨 φ = lift-hom 𝑨 η φE : IsSurjective ∣ φ ∣ φE = lift-of-epi-is-epi 𝑨 ηE pqlem2 : ∀ p q → (p , q) ∈ kernel ∣ hom𝔽 ∣ → 𝑨 ⊧ p ≈ q pqlem2 p q z = λ x → AinMTV p q (kernel-in-theory z) x kerincl : kernel ∣ hom𝔽 ∣ ⊆ kernel ∣ φ ∣ kerincl {p , q} x = ∣ φ ∣ p ≡⟨ (free-lift-interp (wd 𝓥 𝓕⁺) 𝑨 η p)⁻¹ ⟩ (𝑨 ⟦ p ⟧) η ≡⟨ pqlem2 p q x η ⟩ (𝑨 ⟦ q ⟧) η ≡⟨ free-lift-interp (wd 𝓥 𝓕⁺) 𝑨 η q ⟩ ∣ φ ∣ q ∎ goal : epi 𝔽 𝑨 goal = fst (HomFactorEpi (wd 𝓥 (suc (ov α))) 𝑨 φ hom𝔽 kerincl hom𝔽-is-epic φE)
Finally we come to one of the main theorems of this module; it asserts that every algebra in Mod X (Th 𝕍𝒦)
is a homomorphic image of 𝔽
. We prove this below as the function (or proof object) 𝔽-ModTh-epi
. Before that, we prove two auxiliary lemmas.
module _ (pe : pred-ext (ov α)(ov α))(wd : SwellDef) -- extensionality assumptions (Cset : is-set ∣ ℭ ∣) -- truncation assumptions (kuip : blk-uip(Term X)∣ kercon (wd 𝓥 (ov α)){ℭ}homℭ ∣) where 𝔽≤ℭ : (ker[ 𝑻 X ⇒ ℭ ] homℭ ↾ (wd 𝓥 (ov α))) ≤ ℭ 𝔽≤ℭ = FirstHomCorollary|Set (𝑻 X) ℭ homℭ pe (wd 𝓥 (ov α)) Cset kuip
The last piece we need to prove that every model of Th 𝕍𝒦
is a homomorphic image of 𝔽
is a crucial assumption that is taken for granted throughout informal universal algebra—namely, that our collection X
of variable symbols is arbitrarily large and that we have an environment which interprets the variable symbols in every algebra under consideration. In other terms, an environment provides, for every algebra 𝑨
, a surjective mapping η : X → ∣ 𝑨 ∣
from X
onto the domain of 𝑨
.
We do not assert that for an arbitrary type X
such surjective maps exist. Indeed, our X
must is quite special to have this property. Later, we will construct such an X
, but for now we simply postulate its existence. Note that this assumption that an environment exists is only required in the proof of the theorem 𝔽-ModTh-epi
.
With this result in hand, along with what we proved earlier—namely, PS(𝒦) ⊆ SP(𝒦) ⊆ HSP(𝒦) ≡ V 𝒦
—it is not hard to show that 𝔽
belongs to V 𝒦
.
𝔽∈SP : hfunext (ov α)(ov α) → 𝔽 ∈ (S{𝓕}{𝓕⁺} (P{α}{𝓕} 𝒦)) 𝔽∈SP hfe = ssub (class-prod-s-∈-sp hfe) 𝔽≤ℭ 𝔽∈𝕍 : hfunext (ov α)(ov α) → 𝔽 ∈ V 𝒦 𝔽∈𝕍 hfe = SP⊆V' {α}{fe 𝓕 α}{fe 𝓕⁺ 𝓕⁺}{fe 𝓕 𝓕}{𝒦} (𝔽∈SP hfe)
Now that we have all of the necessary ingredients, it is all but trivial to
combine them to prove Birkhoff’s HSP theorem. (Note that since the proof enlists
the help of the 𝔽-ModTh-epi
theorem, we must assume an environment exists,
which is manifested in the premise ∀ 𝑨 → X ↠ 𝑨
.
Birkhoff : hfunext (ov α)(ov α) → (∀ 𝑨 → X ↠ 𝑨) → Mod (Th (V 𝒦)) ⊆ V 𝒦 Birkhoff hfe 𝕏 {𝑨} α = vhimg{𝑩 = 𝑨} (𝔽∈𝕍 hfe) (𝑨 , epi→hom 𝑨 φE , snd ∥ φE ∥) where φE : epi 𝔽 𝑨 φE = 𝔽-ModTh-epi 𝑨 (𝕏 𝑨) α
The converse inclusion, V 𝒦 ⊆ Mod X (Th (V 𝒦))
, is a simple consequence of the
fact that Mod Th
is a closure operator. Nonetheless, completeness demands
that we formalize this inclusion as well, however trivial the proof.
Birkhoff-converse : V{α}{𝓕} 𝒦 ⊆ Mod{X = X} (Th (V 𝒦)) Birkhoff-converse α p q pThq = pThq α
We have thus proved that every variety is an equational class. Readers familiar with the classical formulation of the Birkhoff HSP theorem, as an “if and only if” result, might worry that we haven’t completed the proof. But recall that in the Base.Varieties.Preservation module we proved the following identity preservation lemmas:
𝒦 ⊫ p ≈ q → H 𝒦 ⊫ p ≈ q
𝒦 ⊫ p ≈ q → S 𝒦 ⊫ p ≈ q
𝒦 ⊫ p ≈ q → P 𝒦 ⊫ p ≈ q
From these it follows that every equational class is a variety. Thus, our formal proof of Birkhoff’s theorem is complete.